Chapter 22 — Self-Assessment Quiz
10 questions, ~20 minutes. Aim for 8/10. Each answer cites the section to revisit. This chapter rewards recognition over memorization — if you miss a question, re-run the series through the decision framework in §22.10.
1. The $p$-series $\displaystyle\sum_{n=1}^\infty \frac{1}{n^{p}}$ converges if and only if:
- A) $p > 0$
- B) $p > 1$
- C) $p < 1$
- D) every $p$
Answer
**B) $p > 1$.** The integral test compares it to $\int_1^\infty x^{-p}\,dx$, which converges exactly when $p>1$. The borderline $p=1$ is the harmonic series, which diverges. *§22.2.1.*2. The integral test requires the function $f$ with $a_n=f(n)$ to be:
- A) continuous only
- B) positive, continuous, and decreasing (at least eventually)
- C) any integrable function
- D) increasing and positive
Answer
**B).** All three conditions matter, but the one students forget is *decreasing* — without monotonicity the rectangle-sandwich argument collapses. *§22.2 (Warning).*3. For the ratio test, with $\rho=\displaystyle\lim_{n\to\infty}\left|\frac{a_{n+1}}{a_n}\right|$, the series converges absolutely when:
- A) $\rho > 1$
- B) $\rho < 1$
- C) $\rho = 1$
- D) always
Answer
**B) $\rho < 1$.** If $\rho>1$ it diverges; if $\rho=1$ the test is inconclusive. The threshold matches the geometric series because the ratio test *is* local geometric comparison. *§22.5.*4. Which structure most cleanly signals the root test rather than the ratio test?
- A) a factorial $n!$
- B) the whole term raised to the $n$-th power, $a_n=(\,\cdots\,)^{n}$
- C) terms decaying like $1/n^p$
- D) alternating signs
Answer
**B).** When the entire term is an $n$-th power, $|a_n|^{1/n}$ peels the exponent off in one line. Factorials point to the ratio test; $1/n^p$ decay points to limit comparison; alternating signs point to the alternating series test. *§22.6.*5. A series $\sum a_n$ is conditionally convergent when:
- A) $\sum|a_n|$ converges
- B) $\sum a_n$ converges but $\sum|a_n|$ diverges
- C) it converges to a positive number
- D) it diverges
Answer
**B).** It converges thanks to sign cancellation, yet falls apart once you take absolute values. If $\sum|a_n|$ also converged, it would be *absolutely* convergent — the stronger condition. *§22.8.*6. The series $\displaystyle\sum_{n=1}^\infty \frac{1}{n!}$ (starting at $n=1$) converges; its exact sum is:
- A) $e$
- B) $e - 1$
- C) $\pi$
- D) $\ln 2$
Answer
**B) $e-1$.** The full series $\sum_{n=0}^\infty 1/n! = e$ includes the $n=0$ term, which equals $1$; dropping it leaves $e-1$. Convergence itself follows from the ratio test ($\rho=1/(n+1)\to 0$). *§22.5 (Worked Example 22.5.A); value derived in Chapter 23.*7. The series $\displaystyle\sum_{n=1}^\infty \frac{(-1)^{n}}{n}$ is:
- A) divergent
- B) absolutely convergent
- C) conditionally convergent
- D) equal to $0$
Answer
**C) conditionally convergent.** It converges by the alternating series test, but $\sum 1/n$ diverges. (Its sum is $-\ln 2$; the closely related $\sum(-1)^{n+1}/n=+\ln 2$.) *§22.7–22.8.*8. The Riemann rearrangement theorem says that a conditionally convergent series can be rearranged to:
- A) any real sum you like, or to diverge
- B) only its original sum
- C) only $+\infty$
- D) nothing — its terms cannot be reordered
Answer
**A).** Reorder the *same* terms and you can hit any target, or make it diverge — infinite addition is not commutative. Absolutely convergent series, by contrast, are order-independent. *§22.8 (Math Major Sidebar).*9. For a convergent alternating series satisfying Leibniz's conditions, the error of the partial sum $S_N$ obeys:
- A) $|L-S_N|\le b_N$
- B) $|L-S_N|\le b_{N+1}$
- C) $|L-S_N| = b_N$ exactly
- D) no bound exists
Answer
**B) $|L-S_N|\le b_{N+1}$.** The error is at most the *first omitted term*, and it carries that term's sign. This certified bound is why alternating tails are prized in numerical computing. *§22.7.*10. Faced with a brand-new series $\sum a_n$, the very first thing to check is:
- A) the ratio test
- B) whether $a_n\to 0$ (the divergence test)
- C) a comparison series
- D) the integral test
Answer
**B).** If $a_n\not\to 0$ the series diverges immediately and you stop. Only if $a_n\to 0$ do you proceed down the framework. Remember: $a_n\to 0$ is *necessary but not sufficient* — the harmonic series has $a_n\to 0$ yet diverges. *§22.10, Step 0.*Scoring
- 9–10: Excellent. You are recognizing structure, not just executing tests — you are ready for power series in Chapter 23.
- 7–8: Solid. Re-read the decision framework (§22.10) and drill the "choose the test" problems (Exercises Part F).
- 5–6: Re-read §22.10 and Exercises Parts A–C; practice each test on several series until the routing is automatic.
- Below 5: This is the hardest chapter in the book — that is expected. Slow down, work each test (§22.2–22.7) on five problems apiece, then retake the quiz.